Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.

Open in App

Solution

The steps to draw the triangle of given measurement is as follows:

Draw a line segment AB which is equal to XY + YZ + ZX = 11 cm.

Make an angle ∠Y = 30° from point A and the angle be ∠LAB

Make an angle ∠Z = 90° from point B and the angle be ∠MAB

Bisect ∠LAB and ∠MAB at point X.

Now take the perpendicular bisector of the line XA and XB and the intersection point be Y and Z respectively.

Join XY and XZ

Therefore, XYZ is the required triangle.

Suggest Corrections

130

Similar questions

∠ Y

30^{0}

∠ Z

90^{0}

∠ Y = 30^{\circ}, ∠ Z = 90^{\circ} a n d X Y + Y Z + Z X = 11 c m

Construct a triangle XYZ in which $∠ Y = 30^{\circ}, ∠ Z = 90^{\circ} a n d X Y + Y Z + Z X = 11.$

X Y Z

∠ Y = 30^{o}, ∠ Z = 90^{o}

X Y + Y Z + Z X = 11 c m

∠ Y = 30^{\circ}, ∠ Z = 90^{\circ} a n d X Y + Y Z + Z X = 11 c m

Join BYJU'S Learning Program