Question

Construct a triangle $XYZ$ whose perimeter $15cm$ and whose base angles are ${60}^{\circ }$ and ${70}^{\circ }$

Answer 1

1. Draw a line segment $PQ=XY+YZ+XZ=15cm$

2. Make $\angle LPQ={60}^0$ and $\angle MQP={70}^0$

3. Now bisect $\angle LPQ$ and $\angle MQP$ such that their bisection meet at X.

4. Draw perpendicular bisectors of $XP$ and $XQ$ as $AB$ and $CD$ intersecting $PQ$ at $Y$ and $Z$ respectively.

5. Join $XY$ and $XZ$.