Construct a truth table to negate the proposition : $\sim p \to q$

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Solution

Truth table
p q $\sim p$ $\sim p \to q$ $\sim (\sim p \to q)$
T F F T F
F T T T F
T T F T F
F F T F T

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Similar questions

I f t h e p r o p o s i t i o n \neg p \Rightarrow q i s t r u e,

\neg P \lor (p \Rightarrow q) w h e r e, \neg i s n e g a t i o n,^{'} \lor^{'}

\Rightarrow

(p \land q) \lor [\sim (p \land q)]

(p \land q) \lor (- r)

p \land (\sim p \lor q)

p \lor (\sim p \land q)

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