Question

Construct $∆$ ABC, in which $\angle$B = ${70}^{°}$, $\angle$C = ${60}^{°}$ , AB + BC + AC = 11.2 cm.

Answer 1

Steps of construction:
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(1) Draw seg XY of 11.2 cm length.
(2) Draw a ray making angle of 35° at point X.
(3) Draw another ray making an angle of 30° at point Y.
(4) Name the point of intersection of the two rays as A.
(5) Draw the perpendicular bisector of seg AX and seg AY.
Name the points as B and C respectively where the perpendicular bisectors intersect line XY.
(6) Draw seg AB and seg AC.

Therefore, △ABC is the required triangle.