Question

Construct $△ABC$ in which $BC=4cm,$ $\angle B={50}^{\circ }$ and $\angle C={70}^{\circ }.$

Answer 1

Steps of construction:

• Draw a line segment $BC$ of length $4cm.$

• Draw $\angle CBX$ such that $\angle CBX={50}^{\circ }.$

• Draw $\angle BCY$ with $Y$ on the same side of $BC$ as $X$ such that $\angle BCY={70}^{\circ }.$

• Let $CY$ and $BX$ intersect at $A.$

• $ABC$ is the required triangle.