You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Construction of Isosceles Triangle Whose Base and Corresponding Altitude Are Given

Construct ABC...

Question

Construct $∆$ ABC, in which BC =5.2 cm, $∠$ ACB = $45^{°}$ and perimeter of $∆$ ABC is 10 cm.

Open in App

Solution

Perimeter of △ABC = 10 cm
⇒ AB + BC + AC = 10 cm
⇒ AB + 5.2 + AC = 10 cm
⇒ AB + AC = 4.8 cm
A triangle can be only possible if the sum of the sides of a traingle is greater than the third side.
But here, AB + AC < BC
Hence, the construction of △ABC is not possible.

Suggest Corrections

Similar questions

Q. Write the steps to construct

△ A B C

, in which

B C = 5.2 c m

∠ A C B = 45^{\circ}

and perimeter of

△ A B C

10 c m

$△ A B C \sim △ D E F$ . $△ A B C$ is such that $A B = 5.2 c m, B C = 4.6 c m$ , $∠ B = 45^{\circ}$ and $\frac{B C}{E F} = \frac{2}{3}$ ; Construct $△ D E F$ .

△ A B C

in which

A B = 5.4 cm, ∠ C A B = 45^{\circ}

and

A C + B C = 9 cm

. Then, perimeter of

Δ A B C

Q. Construct

∆

ABC, in which BC = 6.2 cm,

∠

ACB=

50^{°}

, AB + AC = 9.8 cm

Q. Construct a ∆ABC in which AB = AC = 5.2 cm and ∠A = 120°. Draw AD ⊥ BC.

Join BYJU'S Learning Program

Construct ∆ ABC, in which BC =5.2 cm, ∠ACB = 45° and perimeter of ∆ ABC is 10 cm.

Perimeter of △ABC = 10 cm ⇒ AB + BC + AC = 10 cm ⇒ AB + 5.2 + AC = 10 cm ⇒ AB + AC = 4.8 cm A triangle can be only possible if the sum of the sides of a traingle is greater than the third side. But here, AB + AC < BC Hence, the construction of △ABC is not possible.

Construct $∆$ ABC, in which BC =5.2 cm, $∠$ ACB = $45^{°}$ and perimeter of $∆$ ABC is 10 cm.

Perimeter of △ABC = 10 cm
⇒ AB + BC + AC = 10 cm
⇒ AB + 5.2 + AC = 10 cm
⇒ AB + AC = 4.8 cm
A triangle can be only possible if the sum of the sides of a traingle is greater than the third side.
But here, AB + AC < BC
Hence, the construction of △ABC is not possible.