Question

Construct $∆$ ABC such that $\angle$B = ${100}^{°}$ , BC = 6.4 cm, $\angle$C = ${50}^{°}$ and construct its incircle.

Answer 1

Steps of construction:
1. Draw BC = 6.4 cm
2. Draw$\angle$B = ${100}^{°}$ and $\angle$C = ${50}^{°}$ using the protractor. Where the rays YB and XC meet, name the point as A.
$∆$ABC is thus obtained.
3. Construct the angle bisectors of $\angle$B and $\angle$C and let them meet at point O.
4. Through point O, draw a perpendicular to line BC. Let the perpendicular meet the line BC at point P.
5. With O as centre and OP as radius, draw a circle inside the $∆$ABC.
This is the required incircle.