Construct ∆ACD such that AC = 5.5 cm, CD = 5 cm, and AD = 5.5 cm. The measure of ∠A is _____ .

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Solution

Steps of construction:
Step 1: Draw line segment AC = 5.5 cm.
Step 2: With A as centre, cut an arc of radius 5.5 cm.
Step 3: With C as centre, cut an arc of radius 5 cm.
Step 4: Mark the point of intersection of the arcs drawn as D.
Step 5: Join A and D, and C and D.

From the above construction, measure ∠A using protractor.
∠A = 54°

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∠ A

A B C D,

B C = 4.5 c m, A D = 5.5 c m

C D = 5 c m

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B D = 7 c m

△ A B C

∠ A C D = 90 °

Consruct a quadrilateral ABCD such that AB=BC=5.5 cm,CD=4 cm, DA=6.3 cm, and AC=9.4 cm, Measure BD.

A B C D

A B = 5.5 c m, A D = 4.4 c m, C D = 6.5 c m, A C = 6.5 c m

B D = 7.1 c m

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