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Question

Question 1
Construct an angle of
90 at the initial point of a given ray and justify the construction.

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Solution

Steps to construct an angle of 90
(i) Let us take a ray PQ with initial point P and draw an arc of some radius taking point P as its centre, which intersects PQ at R.
(ii) Taking R as the centre and with the same radius as before, draw an arc intersecting the previously drawn arc at S.
(iii) Taking S as the centre and with the same radius as before, draw an arc intersecting the arc at T(see figure).
(iv) Taking S and T as centre, draw an arc of same radius to intersect each other at U.
(v) Join PU, which is the required ray that makes an angle of 90 with the given ray PQ.


Justification
We can justify the construction if we can prove UPQ=90
For this, join PS and PT.


We have, SPQ=TPS=60
In (iii) and (iv) steps of this construction, PU was drawn as the bisector of TPS.
UPS=12×60=30
Also, UPQ=SPQ+UPS
=60+30
=90




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