Construct an equation using x-23- such that the numerical factor of x is 45 in the equation-

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Question

Construct an equation using $x = \frac{2}{3}$ , such that the numerical factor of $x$ is $\frac{4}{5}$ in the equation.

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Solve equation, given below, using factorisation method:

$(x + 3)^{2} - 4 (x + 3) - 5 = 0$

Solve equation, given below, using factorisation method:

$\frac{5}{x - 2} - \frac{3}{x + 6} = \frac{4}{x}$

(x + 3)^{2} - 4 (x + 3) - 5 = 0

\frac{5}{x - 2} - \frac{3}{x + 6} = \frac{4}{x}

Using quadratic formula, factorize the equation : [3 MARK]
$5 x^{2} - 10 x + 3 = 0$

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