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Question

Construct an equilateral triangle each of whose altitudes measures 5.4 cm. Measure each of its sides.

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Solution


Steps of construction:
1. Draw a line XY.
2. Mark any point P.
3. From P draw PQ XY.
4. From P, set off PA = 5.4 cm, cutting PQ at A.
5. Construct PAB = 30° and PAC = 30°, meeting XY at B and C, respectively.

Thus, ABC is the required triangle. Measure of each side is 6 cm.

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