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Question
Construct an equilateral triangle of side 5.5 cm.
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Solution
To construct: Δ ABC where AB = BC = CA = 5.5 cm
Steps of construction
(a) Draw a line segment BC = 5.5 cm
(b) Taking points B and C as centers and radius 5.5 cm, draw arcs which intersect at point A.
(c) Join AB and AC.
It is the required Δ ABC.
Steps of construction
(a) Draw a line segment BC = 5.5 cm
(b) Taking points B and C as centers and radius 5.5 cm, draw arcs which intersect at point A.
(c) Join AB and AC.
It is the required Δ ABC.
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