Question 3
Construct an isosceles right angled triangle ABC, where $∠$ ACB= $90^{\circ}$ and AC = 6cm.

Open in App

Solution

To construct: An isosceles right angled triangle ABC where $∠$ C = $90^{\circ}$ ,AC = BC = 6 cm.
Steps of construction:

(a) Draw a line segment AC = 6cm
(b) At point C, draw XC $⊥$ CA.
(c) Taking C as centre and radius 6cm, draw an arc.
(d) This are cuts CS at point B.
(e) Join BA.
It is the required isosceles right angled triangle ABC.

Suggest Corrections

Similar questions

∠

90^{\circ}

A B C

m ∠ A C B = 90^{o}

A C = 6 c m

A B^{2} = 2 A C^{2}

In $△$ ABC, $∠$ ABC = 90 $^{\circ}$ , $∠$ BAC = 45 $^{\circ}$ and $∠$ ACB = 45 $^{\circ}$ . What is this triangle called?

In $△$ ABC, ∠ABC = 90 $^{\circ}$ ∠BAC = 45 $^{\circ}$ ∠ACB = 45 $^{\circ}$ . What is this triangle called?

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program