Construct an isosceles right angled triangle ABC, where $∠$ ACB= $90^{\circ}$ and AC = 6cm.

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Solution

To construct: An isosceles right angled triangle ABC where $∠$ C = $90^{\circ}$ ,AC = BC = 6 cm.
Steps of construction:

(a) Draw a line segment AC = 6cm
(b) At point C, draw XC $⊥$ CA.
(c) Taking C as centre and radius 6cm, draw an arc.
(d) This are cuts CS at point B.
(e) Join BA.
It is the required isosceles right angled triangle ABC.

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In $△$ ABC, $∠$ ABC = 90 $^{\circ}$ , $∠$ BAC = 45 $^{\circ}$ and $∠$ ACB = 45 $^{\circ}$ . What is this triangle called?

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