Construct an isosceles right-angled triangle ABC, where, m∠ACB = 90° and AC = 6 cm.

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Solution

In an isosceles triangle, the lengths of any two sides are equal.

Let in ΔABC, AC = BC = 6 cm. A rough sketch of this ΔABC is as follows.

The steps of construction are as follows.

(i) Draw a line segment AC of length 6 cm.

(ii) At point C, draw a ray CX making an angle of 90º with AC.

(iii) Taking point C as centre, draw an arc of 6 cm radius to intersect CX at point B.

(iv) Join A to B to obtain the required ΔABC.

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Question 3
Construct an isosceles right angled triangle ABC, where $∠$ ACB= $90^{\circ}$ and AC = 6cm.

A B^{2} = 2 A C^{2}

In $△$ ABC, $∠$ ABC = 90 $^{\circ}$ , $∠$ BAC = 45 $^{\circ}$ and $∠$ ACB = 45 $^{\circ}$ . What is this triangle called?

In $△$ ABC, ∠ABC = 90 $^{\circ}$ ∠BAC = 45 $^{\circ}$ ∠ACB = 45 $^{\circ}$ . What is this triangle called?

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