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Question

Construct an isosceles triangle whose base is 8cm and altitude 4cm and then another triangle whose sides are 112 times the corresponding sides of the isosceles triangle.

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Solution

Steps of construction:
1. Draw a base BC of length 8 cm.
2. Draw the perpendicular bisector of BC and name it PQ. Let it intersect BC in M.
3. From M, mark an arc A at a distance of 4 cm on PQ.
4. Join BA and CB. ABC is the first isosceles triangle.
5. Extend BC and BA. Place the pointed end of the compass at C and mark an arc of radius CM on the opposite side of M on the extended segment BC. Mark the point as D (Since CM is half of BC, BD will be BC+0.5BC=1.5BC)
6. From D, draw a line parallel to AC and let it intersect the extended segment AB at E.

EBD is the required similar triangle.

499210_465204_ans_2ba37ad11e8d4083a4723b6ec1ec0d25.png

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