Construct any pentagon ABCDE and then construct a triangle (PCQ) of area equal to the area of ABCDE and one of whose vertices in C. Which of the following is the correct diagram for the triangle PCQ?
Let ABCDE be a pentagon. We have to construct a triangle of area equal to the area of ABCDE and one of whose vertices is C.
Method of Construction:
(1) Let us draw the diagonals CE and CA of the pentagon ABCDE
(2) Draw DG through D parallel to CE
(3) Draw BF through B parallel to CA
(4) Produce AE (on the left side), which intersects DG at P.
(5) Produce EA which intersects BF at Q
(6) C, P and C, Q are joined.
Then, ΔPCQ is the required triangle to be constructed.
∴ Area of ΔPCQ = Area of pentagon ABCDE.