Construct ΔABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B.

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Solution

The steps of construction are as follows.

(i) Draw a line segment BC of length 6 cm.

(ii) Taking point C as centre, draw an arc of 6.5 cm radius.

(iii) Taking point B as centre, draw an arc of radius 2.5 cm to meet the previous arc at point A.

(iv) Join A to B and C.

ΔABC is the required triangle. ∠B can be measured with the help of protractor. It comes to 90º.

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Question 4
Construct $Δ$ ABC such that AB = 2.5 cm, BC = 6cm and AC = 6.5 cm. Measure $∠$ B.

△ A B C

A B = 2.5 c m, B C = 6 c m

A C = 6.5 c m

∠ B

Δ A B C

B C = 6 c m

∠ A B C = 100^{0}

A C - A B = 2.5 c m

∆

∠

100^{°}

-

Δ

∠

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