Question

Construct $\Delta$ ABC, given $\angle A={60}^{\circ },\angle B={30}^{\circ }$ and AB = 5.8 cm.

Answer 1

To construct: $\Delta$ ABC, given $\angle A={60}^{\circ },\angle B={30}^{\circ }$ and AB = 5.8 cm.
Steps of construction:

(a) Draw a line segment AB = 5.8 cm.
(b) At point A, draw an $\angle YAB={60}^{\circ }$ with the help of compass. (c) At point B, draw $\angle XBA={30}^{\circ }$ with the help of compass.
(d) AY and BX intersect at the point C.
It is the required triangle ABC.