Question

Construct $\Delta$ABC such that AB = 6 cm, BC = 5 cm, and AC = 9 cm. The measure of $\angle C$ is .

• A. 39°
• B. 49°
• C. 55°

Answer 1

The correct option is A 39°

Steps of construction:
Step 1: Draw a line segment AB = 6 cm.
Step 2: Take A as centre and cut an arc of radius 9 cm.
Step 3: Take B as centre and cut an arc of radius 5 cm.
Step 4: Mark the intersection point as C.
From above construction, measure $\angle C$ using protractor.
We get $\angle C$ = 39°