Question

Construct $\Delta ABC$, such that $BC=6cm$,$\angle ABC={100}^0$ and $AC-AB=2.5cm$.

Answer 1

Step 1: Construct a straight line BC = 6 cm.

Step 2: At point B, construct an angle of ${100}^o$

Step 3: Below the line BC,on the arm of this angle mark point X at a distance of 2.5 cm from B

Step 4: Join X to C.

Step 5: Now the copy the angle formed at X on C.

Step 6: Extend the arms of both the angles and mark their intersection as A.