Question

Construct $\Delta$DEF such that DE $=5$ cm, DF $=3$ cm and $\angle$EDF = ${90}^{\circ }$.
[3 marks]

Answer 1

Steps of construction:
(a) Draw line segment DF $=3$ cm.
(b) At point D, draw an angle of ${90}^{\circ }$ with the help of compass i.e., $\angle$XDF $={90}^{\circ }$
(c) Taking D as centre, draw an arc of radius 5 cm, which cuts DX at the point E.
(d) Join EF.
[1.5 marks]

[1.5 marks]