Question

Construct $\Delta$ DEF such that DE = 5 cm, DF = 3 cm and $\angle$ EDF = ${90}^{\circ }$

Answer 1

To Construct: $\Delta$ DEF where DE=5cm, DF=3cm and $\angle$ EDF = ${90}^{\circ }$
Steps of construction:


(a) Draw a line segment DF=3cm.
(b) At point D, draw an angle of 90°with the help of compass i.e., $\angle$ XDF = ${90}^{\circ }$
(c) Taking D as center, draw an arc of radius 5cm, which cuts DX at the point E.
(d) Join EF.
It is the required right angled triangle DEF.