Construct - PQR- given PQ -6-5 cm - PR -7 cm- and QR -8 cm -3 MARKS-

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Standard VII

Mathematics

Classification of Triangles Based on Angles

Construct Δ P...

Question

Construct $Δ P Q R$ , given $¯ ¯¯¯¯¯¯ ¯ P Q = 6.5 c m, ¯ ¯¯¯¯¯¯ ¯ P R = 7 c m$ , and $¯ ¯¯¯¯¯¯¯ ¯ Q R = 8 c m$ [3 MARKS]

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Solution

Construction: 2 Marks
Steps: 1 Mark

1) Draw $¯ ¯¯¯¯¯¯ ¯ P Q = 6.5 c m$

2) With P as centre, draw an arc with radius equal to 7 cm.

3) With Q as centre, draw another arc with radius 8 cm to cut the previous arc at R.

4) Join R to P and Q. PQR is the required triangle.

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[4 MARKS]

Constructa $Δ P Q R,$ in which PQ = 6 cm, QR = 7 cm and PR = 8 cm. Then, construct another triangle whose sides are $\frac{4}{5}$ to,of the corresponding sides of $Δ P Q R$ .

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Construct ΔPQR, given ¯¯¯¯¯¯¯¯PQ=6.5 cm,¯¯¯¯¯¯¯¯PR=7 cm, and ¯¯¯¯¯¯¯¯¯QR=8 cm [3 MARKS]

Construction: 2 Marks Steps: 1 Mark 1) Draw ¯¯¯¯¯¯¯¯PQ=6.5 cm 2) With P as centre, draw an arc with radius equal to 7 cm. 3) With Q as centre, draw another arc with radius 8 cm to cut the previous arc at R. 4) Join R to P and Q. PQR is the required triangle.

Construct $Δ P Q R$ , given $¯ ¯¯¯¯¯¯ ¯ P Q = 6.5 c m, ¯ ¯¯¯¯¯¯ ¯ P R = 7 c m$ , and $¯ ¯¯¯¯¯¯¯ ¯ Q R = 8 c m$ [3 MARKS]

Construction: 2 Marks
Steps: 1 Mark

1) Draw $¯ ¯¯¯¯¯¯ ¯ P Q = 6.5 c m$

2) With P as centre, draw an arc with radius equal to 7 cm.

3) With Q as centre, draw another arc with radius 8 cm to cut the previous arc at R.

4) Join R to P and Q. PQR is the required triangle.