Question

Construct $\Delta$PQR if PQ$=5$ cm, m$\angle$PQR $={105}^o$ and m$\angle$QRP$={40}^o$.

Answer 1

$\angle PQR+\angle QRP+\angle RPQ=180$

$105+40+\angle RPQ=180$

$145+\angle RPQ=180$

$\angle RPQ=180-145$

$\angle RPQ=35$
Draw $PQ=5cm$

Draw angle $P=35°$
Draw angle $Q=105°$
They intersect at point $R=40°$