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Question

Construct Δ PQR if PQ=5cm, PQR=105 and QRP=35.

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Solution

GivenPQR=105 andQRP=40We know that sum of angles of a triangles is 180.PQR+QRP+QPR=180105+40+QPR=180145+QPR=180QPR=180145QPR=35To construct:ΔPQR wherep=35,Q=105 and PQ=5 cmSteps of construction:

(a) Draw a line segment PQ=5cm.
(b) At point P, draw XPQ=35 with the help of protractor.
(c) At point Q, draw YQP=105 with the help of protractor.
(d) XP and YQ intersect at point R.
It is the required triangle PQR.

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