Question

Construct $\Delta PQR$, such that $QR=6.5cm$, $\angle PQR={60}^0$ and $PQ-PR=2.5cm$.

Answer 1

Step 1: Construct a straight line QR = 6.5 cm.

Step 2: At point Q, construct an angle of ${60}^o$

Step 3: On the arm of this angle mark point X at a distance of 2.5 cm from Q

Step 4: Join X to R.

Step 5: Now the copy the angle formed at X on R.

Step 6: Extend the arms of both the angles and mark their intersection as P.