Question

Construct $\Delta TEN$ such that TE = 3 cm, $\angle E={90}^o$ and NE = 4 cm.

Answer 1

Step: $1$: Draw a line NE$=4$cm

Step: $2$: Then construct a ${90}^o$ angle using compass.

Step: $3$: Measuring $3$cm length from the tip of compass mark an arc at point T.

Step: $4$: Join the points N and T.

Step: $5$: Hence $\Delta$TEN is the required triangle, TN$=5$cm.