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Construction of Incircle of a Triangle

Construct Δ E...

Question

Construct ∆EFG from the given measures. l(FG) = 5 cm, m $∠$ EFG = 90^°, l(EG) = 7 cm.

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Solution

Steps of constructions:

(1) Draw seg FG of length 5 cm.
(2) Draw ray FA such that ∠GFA = 90°.
(3) Draw an arc of 7 cm from the vertex G, cutting the ray FA at E.

Therefore, △DEF is the required triangle.

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Δ E F G

from the given measures.

l (F G) = 5 c m

m ∠ E F G = 90^{o}

l (E G) = 7 c m

Q. Construct triangles of the measures given below.
In ∆EFG, l(EG) = 6 cm, m∠F = 65^°, m∠G = 45^°

Q. What is the approximate length of the longer leg of triangle

E F G

?

Q. In □DEFG, l(DE) = 5 cm, l(EF) = 6 cm, l(FG) = 7 cm, l(DG) = 3 cm and l(DF) = 9 cm.

Construct ΔDEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°.

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Construction of Incircle of a Triangle

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