Locus of the Points Equidistant From Two Given Points
Construct ...
Question
Construct ABC such that BC = 7.8 cm , BAC = 100 and Median AM = 3.5 cm.
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Solution
Steps of construction: (i) Draw a line segment BC = 7.8 cm. (ii) Through B, draw BY such that CBY= 100. (iii) Draw BXBY. (iv) Draw the perpendicular bisector of BC intersecting BX at O and BC at M. (v) With O as the centre and OB as the radius, draw a circle. (vi) The minor arc BWC of the circle contains the vertical 100 (vii) With M as the centre, draw an arc of radius 3.5 cm meeting the circle at A and A'. Thus, A'BC or ABC is the required triangle.