Question

Construct $△\mathrm{ABC}$ having given $\mathrm{AB}=4.8\mathrm{cm}$, $\mathrm{BC}=5.2\mathrm{cm}$, and $\angle \mathrm{B}=40$, How many triangles are possible with common base BC?

Answer 1

Step 1: Draw a line $\mathrm{AB}=4.8\mathrm{cm}$

Step 2: from point B draw a line BD making an angle of $40°$

Step 3: With B as the center and radius $5.2\mathrm{cm}$ a mark a point C

Step 4: Join AC

Here, we get the required triangle ADB and

Similarly, we can construct another triangle with the same base BC which is $△\mathrm{BCM}$ as shown below.

Hence, two triangles are possible with a common base BC.