Construct $△ ABC$ , in which $AB = 5.5 cm$ , $BC = 5.2 cm$ and $AC = 4.3 cm .$

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Solution

Step 1: Draw a line $AB = 5.5 cm$
Step 2: With B as center and radius $5.2 cm$ draw an arc.
Step 3: With A as center and radius $4.3 cm$ draw an arc
Step 4: Join AC and BC
Hence, $△ A B C$ is the required triangle.

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Construct a quadrilateral PQRS in which PQ = 4.5 cm, QR = 5.2 cm, RS = 5.5 cm, PS = 4 cm, and ∠PQR = 120°.

P Q R S

P Q = 5.5 c m

Q S = 5.2 c m

P Q R S

P Q = 4.5 c m

Q R = 5.2 c m

R S = 5.5 c m

P S = 4 c m

∠ P Q R = 120^{o}

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