Construct $△ ABC$ in which $BC = 4.6 cm$ , $∠ B = 60 °$ and $∠ C = 45 °$ .

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Solution

Step 1: Draw a line $BC = 4.6 cm$
Step 2: From point B draw $∠ B = 60 °$
Step 3: At point C draw $∠ C = 45 °$ and Line PB and CQ intersect at point A
Hence, we construct $△ ABC$

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\frac{BC}{EF} = \frac{2}{3}

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