Question

Construct $△\mathrm{PQR}$ in which $\mathrm{PQ}=5.3\mathrm{cm}$, $\angle \mathrm{P}=60°$ and $\angle \mathrm{Q}=30°$. Measure $\angle \mathrm{R}$. What kind of triangle is this?

Answer 1

Step 1: Draw a line $\mathrm{PQ}=5.3\mathrm{cm}$

Step 2: From point P draw $\angle \mathrm{P}=60°$

Step 3: From point Q draw $\angle \mathrm{Q}=30°$

We get $\angle \mathrm{R}=90°$ [Measuring by protractor]

In any triangle, if any triangle is equal to 90°, the triangle is called a Right angle triangle.

Hence, $△\mathrm{PQR}$ is Right angle triangle.