Question

Construct $∆$ PQR, in which PQ $-$ PR = 2.4 cm, QR = 6.4 cm and $\angle$PQR = ${55}^{°}$ .

Answer 1

​Steps of construction:

(1) Draw seg QR of length 6.4 cm.
(2) Draw ray QA such that ∠RQA = 55°
(3) Take point B on ray QA such that QB = 2.4 cm.
(4) Construct the perpendicular bisector of seg BR.
(5) Name the point of intersection of ray QA and the perpendicular bisector of seg BR as P.
(6) Draw seg PR.

Therefore, △PQR is required triangle.