Question

Construct $∆$PQR, in which QR = 4.2cm $m\angle$Q = ${40}^{°}$ and PQ + PR = 8.5cm

Answer 1

Steps of constructions:

(1) Draw seg QR of length 4.2 cm.
(2) Draw ray QT such that ∠RQT = 40°.
(3) Mark point S on ray QT such that QS = 8.5 cm
(4) Draw seg RS.
(5) Construct the perpendicular bisector of seg RS .
(6) Name the point of intersection of ray QS and the perpendicular bisector of RS as P.
(7) Draw seg PR.
Therefore, △ABC is the required triangle