Construct Quadrilateral GOLD with OL=7.5 cm, GL= 6 cm, GD = 6 cm, LD = 5 cm, OD = 10 cm.

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Solution

Steps of Constructions:

1. Construct $Δ G L D$ using SSS construction method.
2. With L as the centre, draw an arc of radius 7.5 cm.
3. With D as the centre, draw an arc of radius 10 cm. These two arcs intersect at a point.
4. Since O lies on both the arcs, O is the point intersection of the two arcs.
5. Join LO and GO and complete GOLD.
6. GOLD is the required quadrilateral.

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Construct Quadrilateral GOLD with OL=7.5 cm, GL= 6 cm, GD = 6 cm, LD = 5 cm, OD = 10 cm. [3 MARKS]

Question 2
Construct the Quadrilateral GOLD where

OL=7.5 cm, GL=6cm, LD=5cm, OD=10 cm

Construct the following quadrilaterals.

(i) Quadrilateral LIFT

LI = 4 cm

IF = 3 cm

TL = 2.5 cm

LF = 4.5 cm

IT = 4 cm

(ii) Quadrilateral GOLD

OL = 7.5 cm

GL = 6 cm

GD = 6 cm

LD = 5 cm

OD = 10 cm

(iii) Rhombus BEND

BN = 5.6 cm

DE = 6.5 cm

Construct following quadrilaterals

(i) Quadrilateral $L I F T$
$L I = 4 c m$
$I F = 3 c m$
$T L = 2.5 c m$
$L F = 4.5 c m$
$I T = 4 c m$

G O L D

O L = 7.5 c m

G L = 6 c m

G D = 6 c m

L D = 5 c m

O D = 10 c m

B E N D

B N = 5.6 c m

D E = 6.5 c m

Question 2
Construct the Quadrilateral GOLD where

OL=7.5 cm, GL=6cm, LD=5cm, OD=10 cm

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