Question

Construct Rhombus BEND with BN = 5.6 cm, DE = 6.5 cm.

Answer 1

Concept :
BEND is a rhombus
$\Rightarrow BN\perp DE$ and $BO=NO=2.8cm,DO=EO=3.25cm$ [ Since diagonals are perpendicularly bisect each other in rhombus]

Steps of Constructions:

1. Draw BN whose length is 5.6 cm.
2. Construct perpendicular bisector for BN. Let the perpendicular bisector intersects BN at O
3. With O as centre, draw two arcs of radius 3.25cm on either side of BN.
4. Let the arcs intersects the perpendicular bisector at D and E
5. Join BD, ND, BE and NE to complete the rhombus.
6. BEND is the required rhombus BEND.