Construct Rhombus BEND with BN = 5.6 cm, DE = 6.5 cm. [4 MARKS]

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Solution

Concept : 1 Mark
Steps : 1 Mark
Construction: 2 Marks

Concept :
BEND is a rhombus
$\Rightarrow B N ⊥ D E$ and $B O = N O = 2.8 c m, D O = E O = 3.25 c m$ [ Since diagonals are perpendicularly bisect each other in rhombus]

Steps of Constructions:

1. Draw BN whose length is 5.6 cm.
2. Construct perpendicular bisector for BN. Let the perpendicular bisector intersects BN at O
3. With O as centre, draw two arcs of radius 3.25cm on either side of BN.
4. Let the arcs intersects the perpendicular bisector at D and E
5. Join BD, ND, BE and NE to complete the rhombus.
6. BEND is the required rhombus BEND.

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Similar questions

Construct Rhombus $B E N D$ with $B N = 5.6 c m$ , $D E = 6.5 c m$ .

Question 3
Construct the Rhombus BEND where
BN=5.6 cm, DE=6.5 cm

Question 3
Construct the Rhombus BEND where
BN=5.6 cm, DE=6.5 cm

Construct the following quadrilaterals.

(i) Quadrilateral LIFT

LI = 4 cm

IF = 3 cm

TL = 2.5 cm

LF = 4.5 cm

IT = 4 cm

(ii) Quadrilateral GOLD

OL = 7.5 cm

GL = 6 cm

GD = 6 cm

LD = 5 cm

OD = 10 cm

(iii) Rhombus BEND

BN = 5.6 cm

DE = 6.5 cm

Construct following quadrilaterals

(i) Quadrilateral $L I F T$
$L I = 4 c m$
$I F = 3 c m$
$T L = 2.5 c m$
$L F = 4.5 c m$
$I T = 4 c m$

G O L D

O L = 7.5 c m

G L = 6 c m

G D = 6 c m

L D = 5 c m

O D = 10 c m

B E N D

B N = 5.6 c m

D E = 6.5 c m

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