Question

Construct Rhombus $BEND$ with $BN=5.6cm$, $DE=6.5cm$.

Answer 1

As we know that, In a rhombus, the diagonals are perpendicularly bisect each other.
So, our figure look like

Thus, $BEND$ is a rhombus.
$\Rightarrow BN\perp DE$ and $BO=NO=\frac{5.6}{2}=2.8cm,DO=EO=\frac{6.5}{2}=3.25cm$ [ Since diagonals are perpendicularly bisect each other in rhombus]

Steps of Constructions:

1. Draw $BN$ whose length is $5.6cm$.
2. Construct perpendicular bisector for $BN$. Let the perpendicular bisector intersects $BN$ at $O$.
3. With $O$ as centre, draw two arcs of radius $3.25cm$ on either side of $BN$.
4. Let the arcs intersects the perpendicular bisector at $D$ and $E$
5. Join $BD,ND,BE$ and $NE$ to complete the rhombus.
6. $BEND$ is the required rhombus $BEND$.