Question

Construct the bisector of an angle ${75}^o$.

Answer 1

$\left(i\right)$ Draw a line segment $AP$ of any length.

$\left(ii\right)$ Draw an angle of ${75}^o$ from $A$ and name the new point as B.

$\left(iii\right)$ Draw an arc that is centered at the vertex($A$) of the angle. This arc can have a radius of any length.

$\left(iv\right)$ However, it must intersect both sides of the angle. We will call these intersection points as $C$ and $D$. This provides a point on each line that is an equal distance from the vertex of the angle.

$\left(v\right)$ Draw arcs from $C$ and $D$ and name the point of intersection of these arcs as $Q$.

$\left(vi\right)$ Draw a line segment joining points $A$ and $Q$. Then line $AQ$ forms angle bisector of $A$.