Question

Construct the right-angled $\text{△PQR}$, where $\text{m∠Q = 90°}$,$\text{QR = 8 cm}$ and $\text{PR = 10 cm}$.

Answer 1

Let's draw a rough diagram to get an idea about$\text{△PQR}$,

Let's construct$\text{△PQR}$, using the information in the question -

Step 1: Draw the line segment$\text{QR = 8 cm}$, using the ruler -

Step 2: Draw a ray$\text{QX}$, from point to $Q$ making an angle of $90°$ with line segment$\text{QR}$ -

Step 3: Take an arc of radius $\text{10 cm}$ on compass and draw an arc from point $R$, such that it bisect the ray $\text{QX}$ -

Step 4: The bisected point is $P$, join $PR$ to get the required right-angled triangle -

Thus, obtained $\text{△PQR}$ is our required right-angled triangle.