Question

Construct the equilateral triangle whose altitude is 6 cm. Find the side of the triangle.

• A. 5.42 cm
• B. 6.92 cm
• C. 7.08 cm
• D. None of these

Answer 1

The correct option is B 6.92 cm

Steps of Construction:

1. Draw any line segment PQ.

2. Take a point D on PQ and At D, construct perpendicular DR to PQ. From DR, cut off DA = 6 cm.

3. At A, construct $\angle$DAS = $\angle$DAT $=\frac{1}{2}\times {60}^{\circ }$ = 30${}^{\circ }$ on either side of AD.

Let AS and AT meet PQ at points B and C respectively.

Then, ABC is the required equilateral triangle.

After that measure side AB = 6.92 cm