Question

Construct the equilateral triangle whose altitude is 9 cm. Find the side of the triangle.

• A. 10.392 cm
• B. 11.24 cm
• C. 8.25 cm
• D. 12.34 cm

Answer 1

The correct option is A

10.392 cm

Steps of Construction:

1. Draw any line segment PQ.

2. Take a point D on PQ and At D, construct perpendicular DR to PQ. From DR, cut off DA = 9 cm.

3. At A, construct $\angle$DAS = $\angle$DAT = 1/2 × 60${}^{\circ }$ = 30${}^{\circ }$ on either side of AD.

Let AS and AT meet PQ at points B and C respectively.

Then, ABC is the required equilateral triangle.

After measuring side AB = 10.392 cm.