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Question

Construct the graph of the function given below:f(x)=⎪ ⎪⎪ ⎪x1,x<014,x=0x2,x>0 Find f(x) and limx0f(x).

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Solution

The graph consists of the straight line y=x1 for x<0, the point (0,1/4) and the parabola y=x2forx>0.
Now limx0+f(x)=limh0(0+h)2=0 and limx0f(x)=limh0(0h1)=1.
Since limx0+f(x)limh0f(x),
the function f(x) is discontinuous atx=0.

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