Construct the incentre of △ABC with AB=7cm,∠B=50∘ and BC=6cm. Also draw the incircle and measure its inradius
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Solution
Step 1 : Draw the △ABC with the given measurements. Step 2 : Construct the angle bisectors of any two angles (A and B) and let them meet at I. Then I is the incentre of △ABC. Step 3 : With I as an external point drop a perpendicular to any one of the sides to meet at D. Step 4 : With I as centre and ID as radius draw the circle. This circle touches all the sides of the triangle. Inradius=1.8cm