Question

Construct the incircle of $∆$SRN, such that RN = 5.9 cm, RS = 4.9 cm, $\angle$R = 95$°$ and draw incircle of it.

Answer 1

Steps of construction:
1. Draw a line segment RN = 5.9 cm.
2. Draw $\angle \mathrm{NRX}=95°$.
3. With R as the centre and a radius of 4.9 cm, draw an arc cutting RX at S.
4. Join SN.
5. Then $∆$SRN is the required triangle.
6. Draw angle bisectors of $\angle \mathrm{RNS}\mathrm{and}\angle \mathrm{NRS}$ (any two angles) which intersect at I.
7. From point I, draw a perpendicular IL on side RN.
8. Taking IL as the radius, draw the required incircle.