Question

Construct the incircle of the triangle ABC with AB = 7 cm, $\angle$B = 50${}^{\circ }$ and BC = 6 cm. Then its inradius will measure

• A. 1.5 cm
• B. 1.8 cm
• C. 2.1 cm
• D. 2.3 cm

Answer 1

The correct option is B 1.8 cm

• Draw $△$ABC with the given measurements.
• Construct the angle bisectors of any two angles (A and B) and let them meet at I.
• With I as an external point, drop a perpendicular to any one of the sides to meet at D.
• With I as center and ID as radius draw the circle.

Thus we obtain the required incircle.
From the above figure, the measure of the inradius 1.8 cm.