Construct the quadrilateral ABCD with AB = 5cm, BC = 6cm, CD= 7cm, $∠$ ABC = $40^{\circ}$ and $∠$ BCD = $55^{\circ}$ ?

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Solution

Step 1: Draw AB = 5cm.

Step 2: At B, draw an angle of $45^{\circ}$ and mark 6cm along that angle. Mark the point as C.

Step 3: At C, draw an angle of $55^{\circ}$ and mark 7cm along that angle. Mark the point as D.

Step 4: Join point A and D. So, quadrilateral ABCD can be constructed.

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Similar questions

Construct a quadrliateral ABCD; if:

(i) AB = 4.3 cm, BC = 5.4, CD = 5 cm, DA = 4.8 cm and $∠$ ABC = $75^{\circ}$ .

(ii) AB = 6 cm, CD = 4.5 cm, BC = AD = 5 cm and $∠ BCD = 60^{\circ}$

(iii) AB = 8 cm, BC = 5.4 cm, AD = 6 cm, $∠ A = 60^{\circ}$ and $∠ B = 75^{\circ}$ .

(iv) AB = 5 cm, BC = 6.5 cm, CD = 4.8 cm, $∠ B = 75^{\circ}$ and $∠ C = 120^{\circ}$

(v) AB = 6 cm = AC, BC = 4 cm, CD = 5 cm and AD = 4.5 cm.

(vi) AB = AD = 5 cm, BD = 7 cm and BC = DC = 5.5 cm

∠

40^{\circ}

∠

55^{\circ}

Is it possible to construct a unique quadrilateral ABCD with AB = 5cm, BC = 6cm, CD= 7cm , $∠$ ABC = $45^{\circ}$ and $∠$ BCD = $55^{\circ}$ ?

Is it possible to construct a unique quadrilateral ABCD with AB = 5cm, BC = 6cm, CD = 7cm , $∠$ ABC = $45^{\circ}$ and $∠$ BCD = $55^{\circ}$ ?

We can construct an unique quadrilateral ABCD with AB = 4 cm, BC = 6 cm, AC = 7 cm, CD = 5 cm and BD = 8 cm.

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