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Standard VIII

Mathematics

Construction of Special Quadrilaterals

Construct the...

Question

Construct the Quadrilateral DEAR where
DE = 4 cm, EA = 5 cm, AR = 4.5 cm, $∠ E = 60^{\circ}, ∠ A = 90^{\circ}$

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Solution

Given DE = 4 cm, EA = 5 cm, AR = 4.5 cm, $∠ E = 60^{\circ}, ∠ A = 90^{\circ}$

To construct: A quadrilateral DEAR.

Steps of construction:

(a) Draw a line segment DE=4cm.

(b) At point E, construct an angle of $60^{\circ}$

(c) Taking radius 5 cm, draw an arc from point E which intersects at A.

(d) Construct $∠ A = 90^{\circ}$ , draw an arc of radius 4.5 cm with centre A which intersects at R.

(e) Join RD.

It is the required quadrilateral DEAR.

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Similar questions

Construct the quadrilateral $D E A R$ where $D E = 4 c m, E A = 5 c m, A R = 4.5 c m, ∠ E = 60^{\circ}, ∠ A = 90^{\circ}$

Q. Construct the following quadrilaterals:

Quadrilateral

D E A R,

D E = 4 c m,

E A = 5 c m,

A R = 4.5 c m,

∠ E = 60^{o}

and

∠ A = 90^{o}

Construct the following quadrilaterals,

(i) Quadrilateral DEAR

DE = 4 cm

EA = 5 cm

AR = 4.5 cm

∠E = 60°

∠A = 90°

(ii) Quadrilateral TRUE

TR = 3.5 cm

RU = 3 cm

UE = 4 cm

∠R = 75°

∠U = 120°

Question 1
Construct the Quadrilateral DEAR where
DE=4cm, EA=5cm, AR=4.5cm, $∠ E = 60^{\circ}, ∠ A = 90^{\circ}$

Construct the following quadrilaterals.

(i) Quadrilateral MORE

MO = 6 cm

OR = 4.5 cm

∠M = 60°

∠O = 105°

∠R = 105°

(ii) Quadrilateral PLAN

PL = 4 cm

LA = 6.5 cm

∠P = 90°

∠A = 110°

∠N = 85°

(iii) Parallelogram HEAR

HE = 5 cm

EA = 6 cm

∠R = 85°

(iv) Rectangle OKAY

OK = 7 cm

KA = 5 cm

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Construct the Quadrilateral DEAR where DE = 4 cm, EA = 5 cm, AR = 4.5 cm, ∠E=60∘, ∠A=90∘

Construct the Quadrilateral DEAR where
DE = 4 cm, EA = 5 cm, AR = 4.5 cm, $∠ E = 60^{\circ}, ∠ A = 90^{\circ}$